[jacket3ree]

Good old binomial theorem. I think BC gave you the probability of him making only one shot (31%) rather than at at least one of two.

Anyway if he's an 81% free throw shooter, the probability of missing both is 3.6%, the probability of making one and only one is 30.8% and the probability of making both is 65.6%. The probability of making at least one is 96.4%.

The binomial theorem says that Duke really blew it.

Nerd powers, activate! [wonder twins voice]

p = 0.81

q = 1 - p = 0.19

p(0) = q^2 = (0.19)^2 = 0.0361

p(1) = 2pq = (2)(0.81)(0.19) = 0.3078 (BC's 31%)

p(2) = p^2 = (0.81)^2 = .6561

p(at least one) = 1 - p(0) = 1 - 0.0361 = 0.9639

[jacket3ree]

Good old binomial theorem. I think BC gave you the probability of him making only one shot (31%) rather than at at least one of two.

Anyway if he's an 81% free throw shooter, the probability of missing both is 3.6%, the probability of making one and only one is 30.8% and the probability of making both is 65.6%. The probability of making at least one is 96.4%.

The binomial theorem says that Duke really blew it.

Nerd powers, activate! [wonder twins voice]

p = 0.81

q = 1 - p = 0.19

p(0) = q^2 = (0.19)^2 = 0.0361

p(1) = 2pq = (2)(0.81)(0.19) = 0.3078 (BC's 31%)

p(2) = p^2 = (0.81)^2 = .6561

p(at least one) = 1 - p(0) = 1 - 0.0361 = 0.9639